# 2017/2018 WAEC GCE EXPO: MATHEMATICS THEORY AND OBJ QUESTIONS AND ANSWERS NOW AVAILABLE HERE

## 2017/2018 WAEC GCE EXPO: MATHEMATICS THEORY AND OBJ QUESTIONS AND ANSWERS NOW AVAILABLE HERE

Exam Time: Saturday, 9th September, 2017
General Mathematics 2 (Essay)
9.30am – 12noon
General Mathematics 1 (Objective)
2.00pm – 3.30pm
===================

PLS NOTE THIS SYMBOLS

^ means Raise to power
* means multiplication
sqrt or root means Sqr root
/ means division or divide
degree means degree sign that looks like small zero
tita means tita sign that looks like crossed-zero

~invite all your friends here ~

IGNORE ALL ANSWERS POSTED HERE PREVIOUSLY; THE PAPER WAS CHANGED DUE TO EXCESSIVE LEAKAGE. WE ARE SOLVING THE NEW[REAL ONE]. Relax!!!

============================
============================

============================
Maths OBJ:
1–10: CBACDBBDCA
31–40: DACBBCBCCD
41–50: ACCBDABBCD
=======================

(1a)
[2(1/2)+1(3/4)/1(2/5)]/[2(1/4)-1(1/2)]
[5/2+7/4/7/5]/[9/4-3/2]
=[5/2+7/4*5/7]/[9/4-3/2]
[5/2+5/4]/[9/4-3/2]
=[(10+5/4)/(9-6/4)]
=(15/4)/(3/4)
=15/4*4/3
=5

(1b)
From tan60/1*PR/3root2
PR=3root2*1/root3
=3root2/root3*root3/root3
=3root6/3=root6
From sin45/1*root6/x
x=root6*root2
=root12
=root4*3
=2root3

==================================

(2a)
A=p(1+r/100)^n
A=2205000
n=2
r=5%
p=?
2205000=p(1+5/100)^2
2205000=p(1.05)^2
p=2205000/(1.05)^2
p=N2,000,000

(2b)
Area=30cm^2,
h/b=3/2
Area=1/2bh
b=2h/3
30=1/3*2h/3*h
2h^2=30*2*3
h^2=30*2*3/2
h^2=9
h=root9
h=9.49m

==================================

(3)
2x/1-2/5y=2y/1(isosceles angle)
LCM = 5
10x-2y=10y
10x=10y+2y
x=12y/10
x=6y/5……(1)

2x-2/55y+2whole1/4c+1/2+2y=180(sum of angle in a triangle)
2x/1-2y/5+(9/4)x+y/2+2y=180
LCM = 20
40x-8y+45x+10y+40y=3600
40x+45x-8y+50y=3600
95x+42y=3600….(2)

Substitute for x in eq…2
95(6y/5)+42y=3600
19(6y)+42y=3600
114y+42y=3600
156y/156=3600/156
y=23.08
Subst for y in equ…1
x=6(23.08)/5
x=27.69

=========================================

(4)
OSP+OSR=90
44+OSR=90
OSR=90-44=46
But OSR+RSP=180
46+RQP=180
RQP=180-46
RQP=134°

==================================

(5a) Draw a bar chat with the info the table given

(5b)

Median = ((N + 1) / 2)th item

Where:

N = 31

40, 40, 40, 40, 40, 40, 40, 41, 41, 41, 41, 42, 42, 42, 42, 42, 42, 43, 43, 44, 44, 44, 44, 45, 45, 46, 46, 46, 46, 46, 46

Data table

F 7 4 6 2 4 2 6

X 40 41 42 43 44 45 46

Median = ((31 + 1) / 2)th item

Median = (32 / 2)th item

Median = 16th item

Arranging the discrete data in ascending order, We go get:

40, 40, 40, 40, 40, 40, 40, 41, 41, 41, 41, 42, 42, 42, 42, 42, 42, 43, 43, 44, 44, 44, 44, 45, 45, 46, 46, 46, 46, 46, 46

Median = 42

=========================================

(7a)
Log6y+2log6x= 3
Log6y+log6x²= 3
Log6(x²y)= 3
X²y = 6³
X²y = 216
Y= 216/x²

(7b)
(I). Percentage who liked football and volleyball but not boxing = 20

(II)
Percentage who liked exactly two sports = 40 + 20 + 10 = 70
(III). Summing
5+5+10+40+20+10+5+x = 100%
X + 95 = 100
X = 100– 95 = 5%
Percentage who like none= 5%

=========================================

(9a) Diagram

(9b)

a= 360-330 (angle at a point)

=030 °

b=a=030°(alternate angles)

Φ = 090°+030°

= 120°

(i) find distance AC wing.

|AC|²= |BC|²+|AB|²–2|AB||BC|Cos tita

|AC|²= 300²+100²–2(300)(100)Cos120°

= 90000+10000–60000×(-0.5)

=100,000+30,000

= 130,000

|AC| = √130,000 = 360.555KM

=360.56Km(2d.p)

(ii)

find β, applying the first rule

300/Sinβ = 360.56/Sin120

Sinβ = 300sin120/360.56 = 259.81/360.56

= 0.7206

β = sin inverse(0.7206)

= 46°

Therefore the bearing of the plane from A

=330–046

=284°.

=======================================

2017/2018 WAEC GCE EXPO: MATHEMATICS THEORY AND OBJ QUESTIONS AND ANSWERS NOW AVAILABLE HERE

(11)

A=(2,3,4,5,6,7,8,9,10,11,12)

B=10,11,12,13…24)

M=(4,8,12,16,20,24,28)

(a)

Pr(MnA)=3/7

(b)

Pr(MnB^1)1-PrMnB)

=1-4/7

=3/7

(c)

Pr(Mn(AuB)

AuB=(2,3,4,5…14)

Mn(AuB)=(4,8,12,16,20,24

Pr(Mn(AuB)=6/7

-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=

(13a)

x* y = X+Y+2xy

(i)

2*3 = 2+3+2(2)(3)

= 5+12 = 17

(2*3)*5 = 17*5

= 17+5+2(17)(5)

= 22+170

= 192

(ii)

X*7 = x+7+2(x)7

= 15x + 7

X*5 = X+5+2(x)5

= 11x + 5

(x*5)*2 = (11x + 5)*2

= 11x+5+2+2(11x + 5)2

= 11x+5+2+44x+20

= 55x + 27

X*7 = (x*5)*2

15x + 7 = 55x + 27

15x – 55x = 27–7

–40x = 20

X = 20/-40

X = -½

(13b)

PQ=8i+6j

QR=4i+3j

SR=3(PQ)/2 = 3/2(8i+6j)

=12I+9j

(i)

RS = -SR

=-12i-9j

(ii)

PQ+QR+RS

=8i+6j+(-4i+3j)+(-12i-9j)

=8i+6j-4i+3j-12i-9j

= -8i

Mr class cares