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### NABTEB GCE 2017 Mathematics Expo Obj And Theory Questions and Answers Runz – Nov/Dec Expo

#### NABTEB GCE 2017/2018 Mathematics Expo Obj And Theory (Objective And Essay) Questions And Answers – Nov/Dec Expo Runz, 2017/2018 Nabteb Gce Mathematics Expo Obj And Theory Expo, 2017 Nabteb Gce Questions, 2017 Nabteb Gce Mathematics Expo Obj And Theory Runz, 2017 Nabteb Gce Mathematics Expo Obj And Theory questions and answers

**OUR 2018 JAMB RUNZ SUBSCRIPTION WILL COMMENCE FROM 6TH OF DECEMBER.. SUBSCRIBE WITH US TO SCORE 290+..ASSURED… **

**ENGLISH LANGUAGE** QUESTIONS AND ANSWESRS ARE ON OUR DESK NOW… SUBSCRIBE FOR UR PAPERS….

**MATHEMATICS OBJ:**

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1-10: BDCCDCCBBB

11-20: BACDCCCACD

21-30: BADCDCBDCC

31-40: BDCADBCBCB

41-50: ACCDADACBD

**Examclass.net #cares**

**MATHS THEORY**

=========================

**1a)**

123.24base8 – ()base10

= 1*8^2 + 2*8^1 + 3*8^0 + 2*8^-1 + 4*8^-2

= 64 + 16 + 3 + 2/8 + 4/64

= 83 + 1/4 + 1/16

= 83 + 4+1/16

= 83 + 5/16

= 83^5/16base10

**1b)**

8^1/3 * 5^2/3 * 10^-2/3

2^3/3 * 5^2/3 * (2*5)^2/3

2^1 * 5^2/3 * 2^-2/3 * 5^-2/3

2^1 * 2^-2/3 * 5^2/3 * 5^-2/3

2^1-2/3 * 5^2/3-2/3

2^3-2/3 * 5^0

2^1/3 * 1

= 2^1/3

=========================

**2a)**

y=1+2x/x-2

:- 2x+y = ?

= 2x/1 = 1+2x/x-2

= 2x/1+1+2x/x-2

= 2x(x-2)+(1+2x)/x-2

= 2x^2-4x+1+2x/x-2

= 2x^2-2x+1/x-2

**2b)**

if x+1/2 = x-3+5/x

:- x+2/2 – 5/x = x-3

x(x+1)-5(2)/2x = x-3

x^2+x-10 = 2x(x-3)

x^2+x-10 = 2x^2-6x

x^2-2x^2+x+6x-10 = 0

-x^2+7x-10 = 0

x^2-7x+10 = 0

x(x-5)-2(x-5) = 0

(x-2)(x-5) = 0

x=2 or x=5

=========================

**3a)**

victor investment = N6m

nasiru investment = N3.6m

total investment = N9.6m

proft = turnover-investment

= Nxm-N9.6m

nasiru total take home

= 30%+3.6/9.6*70% = 56.25%

= 56.25/100*[Nxm-N9.6m]

3b)

Victor’s collection rate

=N6m/N9.6m*70%

=43.75%

=========================

**4a)**

S = n/2{2a+(n-1)d}

2S = 2an+(n^2-n)d

2S – (n^2-n)d = 2an

a = 2S-(n^2-n)d/2n

**4b)**

a=?, S= -890, d= -5, n=20

but a=2S-(n^2-n)d/2n

a=2(-890)-(20^2-20)-5/2(20)

a=-1780-(400-20)-5/40

a=-1780+380(S)/40

a=-1780+1900/40

a=120/40 = 3

a=3

=========================

**5a)**

X={1,3,5,7,9,11}

Y={2,3,5,7,11,15}

Z={3,6,9,12,15}

U={1,2,3,…15}

**5b)**

A≡X

b≡Y

C≡X

(i)AnBnC={3}

A^1={4,6,8,10,12,13,14,15}

B^1={1,4,6,8,10,12,13,14}

:- n(A^1nB^1nC) = {6,12}

=========================

••••••SECTION B••••••••`

**8a)**

2x-1/x^2+2x-15

**i)**for zero, numerator = 0

2x-1=0

2x=1

x=1/2

**ii)**for undefined fraction, denominator = 0

x^2+2x-15=0

x^2+5x-3x-15=0

x(x+5)-3(x+5)

(x-3)(x+5)=0

x=3 or -5

**8bi)**

internal diameter = 12cm

internal radius = 12/2 = 6cm

thickness = 2cm

extrenal diameter = 12+4=16cm

external radius = 8cm

**i)**volume = 2/3πr^3

= 2/3*22/7{R^3 – r^2}

= 44/21{8^3-6^3}

= 44/21{512-216}

= 44/21{296} = 13024/21

= 620.19cm^3

**8bii)**

Area of top = πr^2

= 22/7{8^2 – 6^2}

= 22/7{64 – 36}

= 22/7{28}

= 22*4

= 88cm

=========================

**10)**

x̅ = Ʃfx/Ʃf = 3035/50 = 60.7

a)mean deviation = Ʃf|d|/Ʃf

= 748.8/50

= 14.98

b)standard deviation = rootƩfd^2/Ʃf

= root16224/50

= root324.48

= 18.01

=========================

**11ai)**

education = 350

medicine = 150

engineering = 200

law = 100

arts = 100

total = 900

angular sector

**i)**

education = 350/900*360

= 140°

**ii)**

medicine = 150/900*360

= 60°

**iii)**

engineering = 200/900*360

= 80°

iv)

law = 100/900*360

= 40°

v)

arts = 100/900*360

= 40°

11aii)

% of students admitted into faculty of education = 350/900*100%

= 350/9

= 38.9%

11bi)

P(B)=3/12 = 1/4

P(W)=4/12 = 1/3

P(R)=5/12

P(one of each ball)=1/4*4/11*5/10* + 1/3*3/11*4/10* + 5/12*3/11*4/10

= 1/22+2/55+1/22

= 5+4+5/110

= 14/110 = 7/55

11bii)

P(at least two red)

= 5/12*P(RRR1)+P(RR1R)+P(RRR)

= 5/12*4/11*7/10 + 5/12*7/11*3/10 + = 5/12*4/11*3/10

= 7/66 + 7/88 + 1/11

= 28+21+24/264

= 73/264

=========================

13a)

gross income = 2,500,000

personal allowance = 150,000

children(3) = 60,000

insurance(2) 2% of gross = 50,000

contribution(2) 8% of gross = 200,000

total = 460,000

taxable income = 204000

a)

Monthly gross pay

= 2,500,000/12

= N208333.33

b)Tax pay

5% 0f 1st N30,000

= 5/100*30,000

= N15,000

10% of next N30,000

= 10/100*30000

= N3,000

15% of next N50,000

= 15/100*50,000

= 7,500

20% of next 50,000

20/100*50,000

N10,000

25% on remaining = 25/100*(2040000-160,000)

= 25/100*1880000

= N470,000

therefore:

tax pay = 1500+300+7500+470000+110,000

= 492,000

monyhly tax = 492,000/12

= N41,000

c)Next pay = 2,500,000 – 49,200

= N2008000

monthly next pay = 2008000/12

= N167333.33

=========================

15a)

R=4%

T=5years

A=142,000

I=?

P=?

But I=PRT/100 = P*4*5/100 = 20P/100

I=P/5

but A=P+I

:- 142,000 = P+P/5

142,000 = 5P+P/5

142,000*5 = 6P

P = 142,000*5/6

P = N118333.33

15b)

cash price = N82,000

deposit = N40,000

instalment = N2,500 for 24months

:- Total instalment = 2,500*24

=N60,000

Total amount paid on hire purchase = 40,000+60,000

= N100,000

difference between cash price and hire purchase

=100,000 – 82,000

N18,000

15c)

for the first year

Depreciates = 3.5/100*55,000 = N1925

actual cost in 1st quarter = N53075

in 2nd quarter

Depreciate 3.5/100*53075 = N1857.63

actual cost in 2nd quarter = N51217.37

3rd quater

Dep = 3.5/100*51217.37 = N1792.61

actual cost in 3rd quarter = N49424.76

4th quarter

Dep = 3.5/100*49424.76 = N1729.87

actual cost in 4th quarter = 47694.76.89

:- at the end of the first year, the bike cost N47694.89

for the second year

1st quarter

dep = 3.5/100*47694.89 = N 1669.32

actual cost = N46025.57

2nd quarter

dep = 3.5/100*46025.57 = N1610.89

actual cost = N44414.68

3rd quarter

dep = 3.5/100*44414.68 = N1554.51

actual value = N42860.06

4th quarter

dep = 3.5/100*42860.06 = 1500.10

actual cost = N41359.96

at the end of 2years cost = N41359.96

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